(x-3)(x+4)=x^2+4

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Solution for (x-3)(x+4)=x^2+4 equation:


Simplifying
(x + -3)(x + 4) = x2 + 4

Reorder the terms:
(-3 + x)(x + 4) = x2 + 4

Reorder the terms:
(-3 + x)(4 + x) = x2 + 4

Multiply (-3 + x) * (4 + x)
(-3(4 + x) + x(4 + x)) = x2 + 4
((4 * -3 + x * -3) + x(4 + x)) = x2 + 4
((-12 + -3x) + x(4 + x)) = x2 + 4
(-12 + -3x + (4 * x + x * x)) = x2 + 4
(-12 + -3x + (4x + x2)) = x2 + 4

Combine like terms: -3x + 4x = 1x
(-12 + 1x + x2) = x2 + 4

Reorder the terms:
-12 + 1x + x2 = 4 + x2

Add '-1x2' to each side of the equation.
-12 + 1x + x2 + -1x2 = 4 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-12 + 1x + 0 = 4 + x2 + -1x2
-12 + 1x = 4 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-12 + 1x = 4 + 0
-12 + 1x = 4

Solving
-12 + 1x = 4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 1x = 4 + 12

Combine like terms: -12 + 12 = 0
0 + 1x = 4 + 12
1x = 4 + 12

Combine like terms: 4 + 12 = 16
1x = 16

Divide each side by '1'.
x = 16

Simplifying
x = 16

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